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Nusc
Helper II
Helper II

Measure to Calculate sum for value in a Column

https://ufile.io/92hq0

 

In the above look is my sample Excel file.

 

I want to create a measure that would calculate the number of Project hours:

 

Case: Category = Project

 

and sum 'Time As a Decimal'

 

How do you do this?

2 ACCEPTED SOLUTIONS
Greg_Deckler
Super User
Super User

Perhaps something like this measure:

 

Measure = 
SUMX(FILTER(ALL('Table'),[Case: Category]="Project"),[Time As Decimal])

@ me in replies or I'll lose your thread!!!
Instead of a Kudo, please vote for this idea
Become an expert!: Enterprise DNA
External Tools: MSHGQM
YouTube Channel!: Microsoft Hates Greg
Latest book!:
The Definitive Guide to Power Query (M)

DAX is easy, CALCULATE makes DAX hard...

View solution in original post

@Nusc ,

 

You may take a look at https://www.sqlbi.com/articles/the-in-operator-in-dax/.

Community Support Team _ Sam Zha
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
Greg_Deckler
Super User
Super User

Perhaps something like this measure:

 

Measure = 
SUMX(FILTER(ALL('Table'),[Case: Category]="Project"),[Time As Decimal])

@ me in replies or I'll lose your thread!!!
Instead of a Kudo, please vote for this idea
Become an expert!: Enterprise DNA
External Tools: MSHGQM
YouTube Channel!: Microsoft Hates Greg
Latest book!:
The Definitive Guide to Power Query (M)

DAX is easy, CALCULATE makes DAX hard...

THat's the correct Greg thank you.

 

What if I want to add support as well?

Measure = 
(
SUMX(FILTER(ALL('Table'),[Case: Category]="Project"),[Time As Decimal])
+

SUMX(FILTER(ALL('Table'),[Case: Category]="Support"),[Time As Decimal])
)/40*14

But I don't trust the number for this calculation.

@Nusc ,

 

You may take a look at https://www.sqlbi.com/articles/the-in-operator-in-dax/.

Community Support Team _ Sam Zha
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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