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7ea8ea
Helper III
Helper III

Measure that display the latest result

Hi all,

 

I have a data set that looks something like this:

GroupValueDate
A81/12/20
B91/12/20
A61/1/20
B81/1/20

 

I would like to create a measure that gives the latest value as the output for each group. For example, in this case, I would like the measure to output 6 for group A, and 8 for group B. I am working with live data. Therefore, data will be updated every month to include the month's group and value. For example, when it is February, 2 new rows will appear with their own unique values. I would like to just pull out the latest values only. Any help would be appreciated. Thanks

2 ACCEPTED SOLUTIONS
amitchandak
Super User
Super User

@7ea8ea , Try a measure like

calculate(max(Table[Value]), filter(Table, Table[Date] = calculate(Min(Table[Date]), allexcept(Table, Table[Group])))

View solution in original post

Two meausres

calculate(max(Table[Value]), filter(Table, Table[Date] = calculate(Min(Table[Date]), allexcept(Table, Table[Group]))) , Table[group] = "A")
calculate(max(Table[Value]), filter(Table, Table[Date] = calculate(Min(Table[Date]), allexcept(Table, Table[Group]))) , Table[group] = "B")

View solution in original post

3 REPLIES 3
amitchandak
Super User
Super User

@7ea8ea , Try a measure like

calculate(max(Table[Value]), filter(Table, Table[Date] = calculate(Min(Table[Date]), allexcept(Table, Table[Group])))

Hi maybe i didnt explain it properly. I would like to create 2 measures. One for group A and one for Group B. 

Two meausres

calculate(max(Table[Value]), filter(Table, Table[Date] = calculate(Min(Table[Date]), allexcept(Table, Table[Group]))) , Table[group] = "A")
calculate(max(Table[Value]), filter(Table, Table[Date] = calculate(Min(Table[Date]), allexcept(Table, Table[Group]))) , Table[group] = "B")

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