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So I have 3 columns involved in this issue. [Name], [Date], and [ID]. The [ID] column is unique but can contain multiple [Name] values for each [ID]. What I want to return is the most recent [Name] based on the [ID] using the [Date] column. How would I go about doing this?
Solved! Go to Solution.
@Anonymous try followin measure
Recent Name = VAR __latestDate = CALCULATE( MAX( Table[Date]), ALLEXCEPT( Table, Table[Id]) ) RETURN CALCULATE( MAX( Table[Name]), Table[Date] = __latestDate )
Add a table visual, put Id and Recent Name measure on and you will have the result
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@Anonymous try followin measure
Recent Name = VAR __latestDate = CALCULATE( MAX( Table[Date]), ALLEXCEPT( Table, Table[Id]) ) RETURN CALCULATE( MAX( Table[Name]), Table[Date] = __latestDate )
Add a table visual, put Id and Recent Name measure on and you will have the result
Subscribe to the @PowerBIHowTo YT channel for an upcoming video on List and Record functions in Power Query!!
Learn Power BI and Fabric - subscribe to our YT channel - Click here: @PowerBIHowTo
If my solution proved useful, I'd be delighted to receive Kudos. When you put effort into asking a question, it's equally thoughtful to acknowledge and give Kudos to the individual who helped you solve the problem. It's a small gesture that shows appreciation and encouragement! ❤
Did I answer your question? Mark my post as a solution. Proud to be a Super User! Appreciate your Kudos 🙂
Feel free to email me with any of your BI needs.
Thank you @parry2k. Is there a way to do this but for a calculated column instead?
Any other ideas? I need a calculated column as I need to use a matrix instead of a table.
Hi,
This can be done in a calculated column but then that column would not refresh when you make a change in a filter/slicer.
Hi @Anonymous
As tested, parry2k's solution can be used in a calcuated column or a measure
If you have any problem, please feel free to ask.
Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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