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ybarsabal
Resolver I
Resolver I

Level of Detail Calculation

How do I achieve the Desired Calculation below (assume this is the entire table)? The calculation would be a sum of [# Students] fixed to the level of [Campus].

 

In Tableau, the calculation would be {FIXED [Campus] : SUM( [# Students] ) }.

 

LOD calc.PNG

6 REPLIES 6
v-cherch-msft
Employee
Employee

Hi @ybarsabal

 

Could you tell me if your problem has been solved? If it is,kindly mark the helpful answer as a solution and welcome to share your own solution. More people will benefit from here. If not, please share more details for us so that we could help further on it.

 

Regards,

Cherie

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
dedelman_clng
Community Champion
Community Champion

Create a measure:

 

Fixed # = CALCULATE(
	SUM(Table4[#Students]), 
	ALLEXCEPT(Table4, Table4[Campus])
)

fixed.png

 

Hope this helps

David

Shoot, I oversimplified my example. So assume that [Campus] and [# Students] are in two different tables (I know that would be unecessary, but play along). The calculation you provided would not work in that case.

How are [Students] and [Campus] related in the model?

 

 

Let me start over. Take the single table on the left. How do I count the number of students (fixed per campus) even when the data is being split by grade level? My follow up question is how to do a unique count?

 

LOD calc 2.PNG

For the fixed #, its the same basic code, just using COUNT instead of SUM

 

Fixed # = CALCULATE(
	COUNT(Table4[Student ID]), 
	ALLEXCEPT(Table4, Table4[Campus])
)

What do you mean by "unique count" ?

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