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## How to create a subtotal based on subgroup

Hi all,

I have a situation in which I want to calculate the weight percentage for each of the panel type by each sector. However, I do not know how to get the subtotal by Sector.

For example: I want to derive the weight percentage, and I need the denominator value which is the total for each sector and the nominator is the total of all the types under each of sector.

I have a horizotal bar chart that break down the visualisation by sector and by panel types.

For some reason the percentage value I compute using ALL function keep getting the wrong value.

Please be advise that the Sector filter and the Type filter are pull in from two independent dimension tables while the spend amount value is pulled from a fact table.

the following are my measure object (i.e. Sector Spend %) and it is not correct:

Sector Spend % = DIVIDE([total_invoice_amt],
Calculate('legal spend'[total_invoice_amt], All('ProfitCenterStructure'[Sector]), ALL('panel types'[Types])))

total_invoice_amt = SUM('legal spend'[InvAmountAUD])

Any idea I misss out? Thanks .. tuff

Desktop screen:

1 ACCEPTED SOLUTION

Accepted Solutions
Resolver II

## Re: How to create a subtotal based on subgroup

Hi @Anonymous ,

If I understand correctly, try this out:

```SECTOR SPEND % =
Var one =
CALCULATE( SUM( 'Table'[total_invoice_amt] ), ALLEXCEPT( 'Table' , 'Table'[Sector] ))

VAR two =
CALCULATE( SUM( 'Table'[total_invoice_amt] ), ALLEXCEPT( 'Table' , 'Table'[Sector] , 'Table'[Types] ))

Return
two / one```

Result:

Let me know if that worked for you.

Cheers

Robin

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Resolver II

## Re: How to create a subtotal based on subgroup

Hi @Anonymous ,

If I understand correctly, try this out:

```SECTOR SPEND % =
Var one =
CALCULATE( SUM( 'Table'[total_invoice_amt] ), ALLEXCEPT( 'Table' , 'Table'[Sector] ))

VAR two =
CALCULATE( SUM( 'Table'[total_invoice_amt] ), ALLEXCEPT( 'Table' , 'Table'[Sector] , 'Table'[Types] ))

Return
two / one```

Result:

Let me know if that worked for you.

Cheers

Robin

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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