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Helper I
Helper I

How to calculate total rows

Hello everyone

Here's another problem I'm trying to solve. How to calculate the totals in this row to get the true sum.

I appreciate any help.

Best regards

Sumit

1 ACCEPTED SOLUTION

Accepted Solutions
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Community Support
Community Support

Re: How to calculate total rows

Hi @sumitghosal ,

 

We can try to use a GROUPBY function in SUMX to meet your requirement, For example, if you put ColumnA and ColumnB in the row field of matrix visual, we can use a new measure to show the result:

 

NewMeasure =
SUMX (
    GROUPBY ( 'Table', 'Table'[ColumnA], 'Table'[ColumnB] ),
    CALCULATE ( [OldMeasure] )
)

 

6.jpg

 

If you want to get the result like 4+6=10, please grouy by the ColumnA.  If it does not work, could you please share the formula of you measure after removing any confidential information?


By the way, PBIX file as attached.


Best regards,

 

 

Community Support Team _ Dong Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
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Super User II
Super User II

Re: How to calculate total rows

@sumitghosal 

any details?


do not hesitate to give a kudo to useful posts and mark solutions as solution
LinkedIn

Highlighted
Community Support
Community Support

Re: How to calculate total rows

Hi @sumitghosal ,

 

We can try to use a GROUPBY function in SUMX to meet your requirement, For example, if you put ColumnA and ColumnB in the row field of matrix visual, we can use a new measure to show the result:

 

NewMeasure =
SUMX (
    GROUPBY ( 'Table', 'Table'[ColumnA], 'Table'[ColumnB] ),
    CALCULATE ( [OldMeasure] )
)

 

6.jpg

 

If you want to get the result like 4+6=10, please grouy by the ColumnA.  If it does not work, could you please share the formula of you measure after removing any confidential information?


By the way, PBIX file as attached.


Best regards,

 

 

Community Support Team _ Dong Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

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