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harryfasb6000
Frequent Visitor

How do I get Max Timestamp for Each Day using DAX

I have a table that updates 1-3x a day. Does anyone know how I can return only the max timestamp for each day using DAX. Thanks.

 

Max Timestamp per Day.png

1 ACCEPTED SOLUTION
v-lili6-msft
Community Support
Community Support

hi  @harryfasb6000 

You could use this formula to create a column 

Column = 
CALCULATE(MAX('Table'[Datetime]),FILTER('Table',FORMAT([Datetime],"yyyy/MM/dd")=FORMAT(EARLIER([Datetime]),"yyyy/MM/dd")))

or use this formula to create a measure

Measure = CALCULATE(MAX('Table'[Datetime]),FILTER(ALLSELECTED('Table'),FORMAT([Datetime],"yyyy/MM/dd")=FORMAT(SELECTEDVALUE('Table'[Datetime]),"yyyy/MM/dd")))

 

Regards,

Lin

Community Support Team _ Lin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

5 REPLIES 5
v-lili6-msft
Community Support
Community Support

hi  @harryfasb6000 

You could use this formula to create a column 

Column = 
CALCULATE(MAX('Table'[Datetime]),FILTER('Table',FORMAT([Datetime],"yyyy/MM/dd")=FORMAT(EARLIER([Datetime]),"yyyy/MM/dd")))

or use this formula to create a measure

Measure = CALCULATE(MAX('Table'[Datetime]),FILTER(ALLSELECTED('Table'),FORMAT([Datetime],"yyyy/MM/dd")=FORMAT(SELECTEDVALUE('Table'[Datetime]),"yyyy/MM/dd")))

 

Regards,

Lin

Community Support Team _ Lin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

Try this

IF(CALCULATE(MAX(Table1[date]),ALLEXCEPT(Table1,Table1[date]))=MAX(Table1[date]),1,0)

And add this measure to visual level filter ans set it to 1.

Thanks. Tried that but couldnt get to work. Do I need to split the column into two ... date, time?

Take out another date column out of using

date = format(table[datetime],"dd/mm/YYYY")

 

and then on visual take max of date time. If you want populate in table a new column then use

maxx(filter(table,table[date]=earlier(table[date])),table[datetime])

 

But this also needs date

 

Appreciate your Kudos. In case, this is the solution you are looking for, mark it as the Solution. In case it does not help, please provide additional information and mark me with @
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Anonymous
Not applicable

Yes that will make it much easier.

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