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iandespradel
Regular Visitor

Help with Visuals and Making Measures or Calculated Columns, %Days Worked, %Broken %Standby

I work in a company that lends equipment and machinery for construction projects.

 

I have +100 equipment, each identify by an unique ID.

 

I have a log of all the borrowed equipment.(Status: "Active", id 1)

 

And a log of all the equipment being repaired.(Status: "Broken", id 2)

 

I dont't have a daily log of all the equipment available, waiting to be borrow (Status: "Standby", id 0)

 

I've combine both log tables, resulting:

 

Date                           ID.Equip             Status
10/5/2020                    A101                 Active
10/5/2020                    A102                 Active
10/5/2020                    A103                 Broken
.
.
.
10/6/2020                    A101                 Active
10/6/2020                    A102                 Broken
10/6/2020                    A103                 Active
.
.
.
10/8/2020                    A101                 Active
10/10/2020                  A102                Broken
11/11/2020                  B103                 Active

 

If an equiment isn't shown in this table, it means it's in "Standby" for that date (the date is not shown either, as it jumps to the next registry). And not all the equipment ids are listed, because not all equipment have had being "active" or "broken" atm.


I also have a database table with a list of all the equipment.
A101
A102
A103
A104
B101
B102

.

.

.

 

And a calendar table.


I want to create a visual that shows the % of the days "Broken" in a month from the total of days

 

And a visual that shows the % of the "Active" days from the "Standby" days

 

And maybe a combination of "Standby", "Active" and "Broken" as a stacked or 100% stacked chart.

 

I've attached and Example of the data and the types of visuals I have in mind:
PowerBI 

Table 1 

Table 2 

1 ACCEPTED SOLUTION
amitchandak
Super User
Super User

@iandespradel , Try like

 

% of the days Broken =
var _tot = countx(equipment,equipment[ID])
return
divide(calculate(distinctcount(Table[ID.Equip]), filter(Table, Table[Status] ="Broken")), _tot)

 

% of the days Active=
var _tot = countx(equipment,equipment[ID])
return
divide(calculate(distinctcount(Table[ID.Equip]), filter(Table, Table[Status] ="Active")), _tot)

View solution in original post

3 REPLIES 3
v-yuaj-msft
Community Support
Community Support

Hi @iandespradel ,

 

Based on your description, you can do some steps as follows.

 

  1. Create a new table that contains all three status.

 

NEW = CROSSJOIN(ALLSELECTED('00_CONTROL'[Fecha]),ALLSELECTED(iBD_Equipos[Ficha]))

 

  1. Add two columns.

 

Status =

var x1=MAXX(FILTER(ALL('00_CONTROL'),'00_CONTROL'[Fecha]=EARLIER('NEW'[Fecha])&&'00_CONTROL'[Ficha]=EARLIER(NEW[Ficha])),[ID.StatusEq])

return

IF(x1<>BLANK(),x1,0)





Ca_Status = SWITCH([Status],1,"Active",2,"Broken",0,"Standby")

 

  1. Create a measure.

 

_total = CALCULATE(COUNT('NEW'[Ficha]),ALLEXCEPT(NEW,NEW[Fecha],NEW[Ca_Status],'NEW'[Fecha].[Month]))

 

  1. Create a 100% stacked chart.

v-yuaj-msft_0-1606698327413.png

 

Result:

v-yuaj-msft_1-1606698327417.png

 

Hope that's what you were looking for.

Best Regards,

Yuna

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

amitchandak
Super User
Super User

@iandespradel , Try like

 

% of the days Broken =
var _tot = countx(equipment,equipment[ID])
return
divide(calculate(distinctcount(Table[ID.Equip]), filter(Table, Table[Status] ="Broken")), _tot)

 

% of the days Active=
var _tot = countx(equipment,equipment[ID])
return
divide(calculate(distinctcount(Table[ID.Equip]), filter(Table, Table[Status] ="Active")), _tot)

Hey, 

Thanks for the reply.

 

The thing is that the table doesn't have all the calendar days. Just the days the equipment were on site. The rest of the days they were on Standby, and those dates are not in the table.

 

But you give me an idea for a possible solution. Let me check and do a test run.

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