Group Aggregated Slicer Values

[Anonymous]

Hi ,

I have four slicer values in raw data : Tab1, Tab2,Tab3,Tab4

I want to show data based four Slicer Values : Tab1,Tab2,Site,Total

Formula 

Site = Tab3 +Tab4

Total = Tab1+Tab2+Tab3+Tab4

Any idea how to do this in Power Bi

Thanks

[amitchandak]

@Anonymous , not very clear. The information you have provided is not making the problem clear to me. Can you please explain with an example.
refer

https://radacad.com/bookmarks-and-buttons-making-power-bi-charts-even-more-interactive

measure slicer
https://radacad.com/change-the-column-or-measure-value-in-a-power-bi-visual-by-selection-of-the-slicer-parameter-table-pattern
https://community.powerbi.com/t5/Desktop/Slicer-MTD-QTD-YTD-to-filter-dates-using-the-slicer/td-p/500115
https://www.youtube.com/watch?v=vlnx7QUVYME

[Anonymous]

Actual Data

Actual Value	Region
1	Tab1
2	Tab2
6	Tab3
9	Tab 4

Below Required

Actual Value	Region
1	Tab1
2	Tab2
15	Site
18	Total

Site = Tab3 +Tab4

Total = Tab1+Tab2+Tab3+Tab4

[v-deddai1-msft · Accepted solution]

Hi @Anonymous ,

You can create a new table for slicer:

Table 2 = UNION(UNION(VALUES('Table'[Region]),ROW("Region","Site")),ROW("Region","Total"))

Then you can create the following measure:

Measure =
SWITCH (
    TRUE (),
    SELECTEDVALUE ( 'Table 2'[Region] ) = "Tab1", CALCULATE ( SUM ( 'Table'[Actual Value] ), 'Table'[Region] = "Tab1" ),
    SELECTEDVALUE ( 'Table 2'[Region] ) = "Tab2", CALCULATE ( SUM ( 'Table'[Actual Value] ), 'Table'[Region] = "Tab2" ),
    SELECTEDVALUE ( 'Table 2'[Region] ) = "Tab3", CALCULATE ( SUM ( 'Table'[Actual Value] ), 'Table'[Region] = "Tab3" ),
    SELECTEDVALUE ( 'Table 2'[Region] ) = "Tab4", CALCULATE ( SUM ( 'Table'[Actual Value] ), 'Table'[Region] = "Tab4" ),
    SELECTEDVALUE ( 'Table 2'[Region] ) = "Site",
        CALCULATE (
            SUM ( 'Table'[Actual Value] ),
            'Table'[Region] = "Tab3"
                || 'Table'[Region] = "Tab4"
        ),
    SELECTEDVALUE ( 'Table 2'[Region] ) = "Total", SUM ( 'Table'[Actual Value] )
)

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Best Regards,

Dedmon Dai