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kevingeorge3 Frequent Visitor

## Geting Count of Days

How would I calculate the number of days in each month between two dates in powerBI?
Example: Given start date of 12/09/2010 and end date 07/11/2010 I would like to get back

09/2010 - 22 days
10/2010 - 31 days
11/2010 - 7 days

The start and end dates vary and could possibly be in the same month or across two months or even more.

1 ACCEPTED SOLUTION

Accepted Solutions Community Support

## Re: Geting Count of Days

You can use the below measures:

``201009 = IF(MIN('Table'[StartDate])>DATE(2010,9,30)||MAX('Table'[EndDate])<DATE(2010,9,1),0,IF(MIN('Table'[StartDate])<=DATE(2010,9,1)&&MAX('Table'[EndDate])>=DATE(2010,9,30),30,IF(MIN('Table'[StartDate])>DATE(2010,9,1)&&MAX('Table'[EndDate])>=DATE(2010,9,30),DATEDIFF(MIN('Table'[StartDate]),DATE(2010,9,30),DAY)+1,IF(MIN('Table'[StartDate])<=DATE(2010,9,1)&&MAX('Table'[EndDate])<DATE(2010,9,30),DATEDIFF(DATE(2010,9,1),MAX('Table'[EndDate]),DAY)+1,DATEDIFF(MIN('Table'[StartDate]),MAX('Table'[EndDate]),DAY)+1))))``
``201010 = IF(MIN('Table'[StartDate])>DATE(2010,10,31)||MAX('Table'[EndDate])<DATE(2010,10,1),0,IF(MIN('Table'[StartDate])<=DATE(2010,10,1)&&MAX('Table'[EndDate])>=DATE(2010,10,30),31,IF(MIN('Table'[StartDate])>DATE(2010,10,1)&&MAX('Table'[EndDate])>=DATE(2010,10,31),DATEDIFF(MIN('Table'[StartDate]),DATE(2010,10,31),DAY)+1,IF(MIN('Table'[StartDate])<=DATE(2010,10,1)&&MAX('Table'[EndDate])<DATE(2010,10,31),DATEDIFF(DATE(2010,10,1),MAX('Table'[EndDate]),DAY)+1,DATEDIFF(MIN('Table'[StartDate]),MAX('Table'[EndDate]),DAY)+1))))``

``201011 = IF(MIN('Table'[StartDate])>DATE(2010,11,30)||MAX('Table'[EndDate])<DATE(2010,11,1),0,IF(MIN('Table'[StartDate])<=DATE(2010,11,1)&&MAX('Table'[EndDate])>=DATE(2010,11,30),30,IF(MIN('Table'[StartDate])>DATE(2010,11,1)&&MAX('Table'[EndDate])>=DATE(2010,11,30),DATEDIFF(MIN('Table'[StartDate]),DATE(2010,11,30),DAY)+1,IF(MIN('Table'[StartDate])<=DATE(2010,11,1)&&MAX('Table'[EndDate])<DATE(2010,11,30),DATEDIFF(DATE(2010,11,1),MAX('Table'[EndDate]),DAY)+1,DATEDIFF(MIN('Table'[StartDate]),MAX('Table'[EndDate]),DAY)+1))))`` You can also use M code to do this, but it would be a little bit complicated, please refer to the similar solved post:

Community Support Team _ Dina Ye
If this post helps, then please consider Accept it as the solution to help the other members find it more
quickly.
5 REPLIES 5 Super User IV

## Re: Geting Count of Days

from where these dates are coming from. Are they part of table or they are selected in Sclicer.

In case it does not help, please provide additional information and mark me with @
My Recent Blogs -Decoding Direct Query - Time Intelligence, Winner Coloring on MAP,
HR Analytics, Power BI Working with Non-Standard TimeAnd Comparing Data Across Date Ranges
Proud to be a Super User! Linkedin

kevingeorge3 Frequent Visitor

## Re: Geting Count of Days

Hello,

they are coming from a table. Super User IV

## Re: Geting Count of Days

Try This a new column not measure

``datediff = datediff(d1,d2,DAY)``

Appreciate your Kudos. In case, this is the solution you are looking for, mark it as the Solution. In case it does not help, please provide additional information and mark me with @
Thanks. My Recent Blog -
https://community.powerbi.com/t5/Community-Blog/Winner-Topper-on-Map-How-to-Color-States-on-a-Map-wi...
https://community.powerbi.com/t5/Community-Blog/HR-Analytics-Active-Employee-Hire-and-Termination-tr...
https://community.powerbi.com/t5/Community-Blog/Power-BI-Working-with-Non-Standard-Time-Periods/ba-p...
https://community.powerbi.com/t5/Community-Blog/Comparing-Data-Across-Date-Ranges/ba-p/823601

In case it does not help, please provide additional information and mark me with @
My Recent Blogs -Decoding Direct Query - Time Intelligence, Winner Coloring on MAP,
HR Analytics, Power BI Working with Non-Standard TimeAnd Comparing Data Across Date Ranges
Proud to be a Super User! Linkedin

kevingeorge3 Frequent Visitor

## Re: Geting Count of Days

That works to get the total days in the period,

so that data reprsents days worked  so if I wanted a chart that shows the number of days worked by each year how would I do that if the start and stop dates have different years? Community Support

## Re: Geting Count of Days

You can use the below measures:

``201009 = IF(MIN('Table'[StartDate])>DATE(2010,9,30)||MAX('Table'[EndDate])<DATE(2010,9,1),0,IF(MIN('Table'[StartDate])<=DATE(2010,9,1)&&MAX('Table'[EndDate])>=DATE(2010,9,30),30,IF(MIN('Table'[StartDate])>DATE(2010,9,1)&&MAX('Table'[EndDate])>=DATE(2010,9,30),DATEDIFF(MIN('Table'[StartDate]),DATE(2010,9,30),DAY)+1,IF(MIN('Table'[StartDate])<=DATE(2010,9,1)&&MAX('Table'[EndDate])<DATE(2010,9,30),DATEDIFF(DATE(2010,9,1),MAX('Table'[EndDate]),DAY)+1,DATEDIFF(MIN('Table'[StartDate]),MAX('Table'[EndDate]),DAY)+1))))``
``201010 = IF(MIN('Table'[StartDate])>DATE(2010,10,31)||MAX('Table'[EndDate])<DATE(2010,10,1),0,IF(MIN('Table'[StartDate])<=DATE(2010,10,1)&&MAX('Table'[EndDate])>=DATE(2010,10,30),31,IF(MIN('Table'[StartDate])>DATE(2010,10,1)&&MAX('Table'[EndDate])>=DATE(2010,10,31),DATEDIFF(MIN('Table'[StartDate]),DATE(2010,10,31),DAY)+1,IF(MIN('Table'[StartDate])<=DATE(2010,10,1)&&MAX('Table'[EndDate])<DATE(2010,10,31),DATEDIFF(DATE(2010,10,1),MAX('Table'[EndDate]),DAY)+1,DATEDIFF(MIN('Table'[StartDate]),MAX('Table'[EndDate]),DAY)+1))))``

``201011 = IF(MIN('Table'[StartDate])>DATE(2010,11,30)||MAX('Table'[EndDate])<DATE(2010,11,1),0,IF(MIN('Table'[StartDate])<=DATE(2010,11,1)&&MAX('Table'[EndDate])>=DATE(2010,11,30),30,IF(MIN('Table'[StartDate])>DATE(2010,11,1)&&MAX('Table'[EndDate])>=DATE(2010,11,30),DATEDIFF(MIN('Table'[StartDate]),DATE(2010,11,30),DAY)+1,IF(MIN('Table'[StartDate])<=DATE(2010,11,1)&&MAX('Table'[EndDate])<DATE(2010,11,30),DATEDIFF(DATE(2010,11,1),MAX('Table'[EndDate]),DAY)+1,DATEDIFF(MIN('Table'[StartDate]),MAX('Table'[EndDate]),DAY)+1))))`` You can also use M code to do this, but it would be a little bit complicated, please refer to the similar solved post:

Community Support Team _ Dina Ye
If this post helps, then please consider Accept it as the solution to help the other members find it more
quickly.

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