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In the screenshot attached A has occurred four times and first occurrence is on 01/01/2020 11:20 and last occurrence is 03/01/2020 11:29. So the date difference between these two is 2 days 9 minutes. (1449 min). Calculation difference in hours or in muntes or in seconds will also work.
I need result table in Power like
A 1449
B X
C X..
Solved! Go to Solution.
Came to know later that simple below measure will also work
DateDiff in Hours = DATEDIFF(MIN(B),MAX(B),HOUR)
Came to know later that simple below measure will also work
DateDiff in Hours = DATEDIFF(MIN(B),MAX(B),HOUR)
Hi @Anonymous ,
Try this measure:
Measure =
VAR Min_ =
CALCULATE(
MIN(Sheet4[Date/time]),
ALLEXCEPT(
sheet4, Sheet4[Item]
)
)
VAR Max_ =
CALCULATE(
MAX(Sheet4[Date/time]),
ALLEXCEPT(
Sheet4, Sheet4[Item]
)
)
RETURN
Measure 2 =
DATEDIFF(
[Min_], [Max_], MINUTE
)
2 days 9 mins = 24*60*2 + 9 = 2889
Best regards,
Lionel Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
You have view data based on column 1
and create a measure to take diff
measure = datediff(Min(Table[Date]),Max(Table[Date]),Minute)
DATEDIFF([Date1],[Date2],MINUTE)
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