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Anonymous
Not applicable

Get Date difference with minutes if possible between first occurrence and last occurrence.

In the screenshot attached A has occurred four times and first occurrence is on 01/01/2020 11:20 and last occurrence is 03/01/2020 11:29. So the date difference between these two is 2 days 9 minutes. (1449 min). Calculation difference in hours or in muntes or in seconds will also work.

 

DateDiff.PNG

I need result table in Power like 

A  1449

B  X

C  X..

 

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Came to know later that simple below measure will also work
DateDiff in Hours = DATEDIFF(MIN(B),MAX(B),HOUR)

View solution in original post

4 REPLIES 4
Anonymous
Not applicable

Came to know later that simple below measure will also work
DateDiff in Hours = DATEDIFF(MIN(B),MAX(B),HOUR)

v-lionel-msft
Community Support
Community Support

Hi @Anonymous ,

 

Try this measure:

 

Measure = 
VAR Min_ = 
CALCULATE(
    MIN(Sheet4[Date/time]),
    ALLEXCEPT(
        sheet4, Sheet4[Item]
    )
)
VAR Max_ = 
CALCULATE(
    MAX(Sheet4[Date/time]),
    ALLEXCEPT(
        Sheet4, Sheet4[Item] 
    )
)
RETURN
Measure 2 = 
DATEDIFF(
    [Min_], [Max_], MINUTE
)

iii9.PNG

2 days 9 mins = 24*60*2 + 9 = 2889

 

 

Best regards,
Lionel Chen

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.


 

amitchandak
Super User
Super User

You have view data based on column 1

and create a measure to take diff

 

measure = datediff(Min(Table[Date]),Max(Table[Date]),Minute)

Greg_Deckler
Super User
Super User

DATEDIFF([Date1],[Date2],MINUTE)


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