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KPME
New Member

Filter Column based on two string options

Hello everyone,

 

for one string filter the following works: 

NewColumn = CALCULATE(DISTINCTCOUNT(table[ID]),FILTER(table,CONTAINSSTRING(table[OPTIONS],"String01")))
 
However for two strings I tried this (but doesn't work):
NewColumn = CALCULATE(DISTINCTCOUNT(table[ID]),FILTER(table,CONTAINSSTRING(table[OPTIONS],"String01"+"String02))))
 
Kind regards
1 ACCEPTED SOLUTION
Ashish_Mathur
Super User
Super User

Hii,

Does this work?

NewColumn = CALCULATE(DISTINCTCOUNT(table[ID]),FILTER(table,CONTAINSSTRING(table[OPTIONS],"String01")||CONTAINSSTRING(table[OPTIONS],"String02")))

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/

View solution in original post

4 REPLIES 4
Ashish_Mathur
Super User
Super User

Hii,

Does this work?

NewColumn = CALCULATE(DISTINCTCOUNT(table[ID]),FILTER(table,CONTAINSSTRING(table[OPTIONS],"String01")||CONTAINSSTRING(table[OPTIONS],"String02")))

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/
Jayee
Responsive Resident
Responsive Resident

Hi @KPME 

 

For the second column use AND (&&), OR (||) operator insted of "+" sign based on your requirement 

 

If this post helps, then please consider Accept it as the solution, Appreciate your Kudos!!

Hey! this doesn't result in any errors, however it does result in an error in the visual which I can't explain 😞 

Jayee
Responsive Resident
Responsive Resident

may be you can provide sameple data without sensitive information so i can able to support you further.

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