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Hi All,
Is it possible to extract date from a text column which looks like this:
Nurcan Türkan- 21.08.1986 |
18.01.1988 |
09.08.1965 |
M1 28.02.1987 |
M2 11.04.1987 |
31.12.1986 |
11.09.1994 |
21.04.1995 |
M1 18.07.1992 |
M2 12.05.1993 |
Fr.09.03.82/ Hr.1.11.79 |
18.05.1993 |
01.05.1971 (Herr |
02.02.1976 (Frau) |
25.04.1993 |
26.07.1980 |
29.04.1973 |
Rube- 29.11.1970/ Hofmann- 02.05.1967 |
Ruzana B- 04.6.75/ Vjaceslav B. 24.9.71 |
13.03.1971 (Frau Schafft) |
26.01.1971 (Herr Anderle) |
Lück 22.11.1988/ Lakatos 25.01.1990 |
Fr. Pütz 25.07.1991/ Hr.Meise 02.04.1991 |
15.10.1993 |
09.06.1971 |
06.05.1974 in Slawgorod |
02.07.1967 |
Fr. L. 21.06.1988/ Hr. K. 11.08.1987 |
12.07.1990 |
15.01.1980 |
23.02.1963 |
03.09.1965 |
Fr. 27.03.1962/ Hr. 24.06.1974 |
10.05.1991 |
19.12.1950 |
Fr. 20.06.1942/ Hr. 10.04.1949 |
I want another column with the date values from the given set. Places where we have 2 date values, it's okay to extract first value only.
Solved! Go to Solution.
Hi AS31,
I'm afraid power bi can't implement too complex string matching, so you should write a regular expression using R Script to achieve the date you want. Install R package "stringr" and implement R Script as below:
# 'dataset' holds the input data for this script library(stringr) pattern <- "\\d+\\.\\d+\\.\\d+" dataset$CleanedDate <- str_extract(dataset$Date, pattern) output <- dataset
The result is like this:
Regards,
Jimmy Tao
Hi AS31,
I'm afraid power bi can't implement too complex string matching, so you should write a regular expression using R Script to achieve the date you want. Install R package "stringr" and implement R Script as below:
# 'dataset' holds the input data for this script library(stringr) pattern <- "\\d+\\.\\d+\\.\\d+" dataset$CleanedDate <- str_extract(dataset$Date, pattern) output <- dataset
The result is like this:
Regards,
Jimmy Tao
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