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CraigDykes Regular Visitor

Efficency calculation

Hello,

I have data, "total time it took to create the part"(time) and "working mins" (Whole Number).

Is here a way to divide one into the other.

This data would then be used to provide a percentage for the machine efficency for the day, week, month etc.

I would really appreciate and help/ suggestions on this  1 ACCEPTED SOLUTION

Accepted Solutions Community Support Team

Re: Efficency calculation

Create a measure like below.Then drag the date column and the measure to a table visual.

```Measure =
DIVIDE (
CALCULATE ( SUM ( Table1[Time_Second] ) ),
CALCULATE ( MAX ( Table1[Working-Second] ) )
)
```

Regards,

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
7 REPLIES 7 Community Support Team

Re: Efficency calculation

You may convent them to seconds columns.Then use the seconds columns to get the percent as requested.

```Time_second =
HOUR ( [Time it took to create the part] ) * 60 * 60
+ MINUTE ( [Time it took to create the part] ) * 60
+ SECOND ( [Time it took to create the part] )
```
`Working_second = Table2[Working mins]*60` Regards,

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
CraigDykes Regular Visitor

Re: Efficency calculation

Im am now having an issue with the division

if i divide Time_Second into Working_Second in a measure it will sum all of the working mins

eg Sum of Thursday working seconds = 172 +172 +171 + 80 + 141 +415 = 1,151

but it also totals all the working seconds 32400 x 6 = 194,400

Is there a way to divide it by a single 32400

(I intend to create report visualisation by day, week month etc so cant select lowest number etc     Community Support Team

Re: Efficency calculation

You may create a measure with MAX function to get it.If it is not your case,please share some sample data and expected output which would be helpful to provide an accurate solution.

```Measure =
DIVIDE ( MAX ( [Working_second] ), SUM ( [Time_Second] ) )
```

Regards,

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
CraigDykes Regular Visitor

Re: Efficency calculation

Apologies @v-cherch-msft

For context;

We have a factory machine that cuts throughout the day.  I wanted to add to the total cutting time together and then divide by the time in the workers shift in order to get the machine utilisation.

on the 16th of april Tuesday i have 8 results

1095 + 183 + 185 + 935 + 977 + 1072 + 1078 + 189 =‬ 5,714 (total seconds of machine in use)

The total working seconds for that day would be 32400

I had intended of calculating the machine usage by dividing the total seconds the machine is in use by the total working seconds in a workers shift ( 5,714/32,400 )  which would be 17.63% FYI on fridays we have different working hours

Thanks Community Support Team

Re: Efficency calculation

```Measure =
DIVIDE (
CALCULATE (
SUM ( Table1[Time_Second] ),
FILTER ( Table1, Table1[Date] = DATE ( 2019, 4, 16 ) )
),
CALCULATE (
MAX ( Table1[Working-Second] ),
FILTER ( Table1, Table1[Date] = DATE ( 2019, 4, 16 ) )
)
)
``` Regards,

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
CraigDykes Regular Visitor

Re: Efficency calculation

Yes that looks to be exactly what i am am looking for.

Is there a way i can do the measure for all the days?

Apologies if this is simple, would be a novice to Dax Community Support Team

Re: Efficency calculation

Create a measure like below.Then drag the date column and the measure to a table visual.

```Measure =
DIVIDE (
CALCULATE ( SUM ( Table1[Time_Second] ) ),
CALCULATE ( MAX ( Table1[Working-Second] ) )
)
```

Regards,

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.