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Regular Visitor

## EARLIER chalenge

Hello Power friends,

I have a table with IT tickets like that:

Id_ticket, date, old_status, new_status,days_to_fix

100,01/01/2018,<blank>,"new ticket" ,0 // user report a problem opening a ticket

100,01/01/2018,"new ticket","working",0 // IT specialist start working on it

100,01/03/2018,"working","fixed", 2 // IT specialist solved it in two days

100,01/04/2018,"fixed" , "working",0 // user was not satisfied with solution and put the ticket on working status again

100,01/09/2018,"working","fixed", 5 // IT specialist got new solution in five days

100,01/10/2018,"fixed","closed", 0 // User accept this solution

The question is: "How can I calculate the "days_to_fix" collum in this example? Note that It has to be filled every time we have a "fixed" on new_status collum.

Thanks for your time and knowledge sharing.

1 ACCEPTED SOLUTION

Accepted Solutions
Established Member

## Re: EARLIER chalenge

Greg gave you the basic construct, and link explaining the concept.

You'll just need to change RETURN portion to only return result when [new_status]="fixed".

So...

```Column =
VAR __max =
MAXX (
FILTER (
ALL ( 'Table' ),
[Id_ticket] = EARLIER ( [Id_ticket] )
&& [date] < EARLIER ( [date] )
&& [new_status] = EARLIER ( [old_status] )
),
[date]
)
RETURN
IF ( [new_status] = "fixed", [date] - __max, 0 )```

Result

6 REPLIES 6
Regular Visitor

## EARLIER chalenge for Power users

Hello Power friends,

I have a table with IT tickets like that:

Id_ticket, date, old_status, new_status,days_to_fix

100,01/01/2018,<blank>,"new ticket" ,0                // user report a problem opening a ticket

100,01/01/2018,"new ticket","working",0               // IT specialist start working on it

100,01/03/2018,"working","fixed", 2                      // IT specialist solved it in two days

100,01/04/2018,"fixed" , "working",0                  // user was not satisfied with solution and put the ticket on working status again

100,01/09/2018,"working","fixed", 5                    // IT specialist got new solution in five days

100,01/10/2018,"fixed","closed", 0                       // User accept this solution

The question is: "How can I calculate the "days_to_fix" collum in this example? Note that It has to be filled every time we have a "fixed" on new_status collum.

Thanks for your time and knowledge sharing.

Super User

## Re: EARLIER chalenge

It is going to look something like:

```Column =
VAR __max = MAXX(FILTER(ALL('Table'),[Id_ticket]=EARLIER([Id_ticket])&&[date]<EARLIER([date])&&[new_status]=EARLIER([old_status])),[date])
RETURN [date] - __max```

See my article on Mean Time Before Failure (MTBF) which uses EARLIER: http://community.powerbi.com/t5/Community-Blog/Mean-Time-Between-Failure-MTBF-and-Power-BI/ba-p/3395...

Proud to be a Datanaut!

Regular Visitor

## Re: EARLIER chalenge

Thanks for your time @Greg_Deckler, but, unfortunately, it didn't worked as expected. If you could check, I´ll be thankfull.

The new collum had a unknown value in the first line (the new ticket) and in the 2nd "working" line.

Thanks.

Established Member

## Re: EARLIER chalenge

Greg gave you the basic construct, and link explaining the concept.

You'll just need to change RETURN portion to only return result when [new_status]="fixed".

So...

```Column =
VAR __max =
MAXX (
FILTER (
ALL ( 'Table' ),
[Id_ticket] = EARLIER ( [Id_ticket] )
&& [date] < EARLIER ( [date] )
&& [new_status] = EARLIER ( [old_status] )
),
[date]
)
RETURN
IF ( [new_status] = "fixed", [date] - __max, 0 )```

Result

Super User

## Re: EARLIER chalenge

Right, I was just trying to give you the general jist of where it was headed. I didn't actually test that code so it's a small miracle it worked at all without some type of syntax error! I only had a couple minutes to respond. Not surprising that you'd get an error for the first row outlier. Probably fixable by checking how many rows are returned using COUNTROWS.

Let me see if I can find some time to get your data loaded and write it out specifically with that data.