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Dyanamic Dimension from measure in power bi

if I have a three Table
1. Dim_Customer : joiningDate, LeavingDate, State, District, Cust_Type, CustID, CustomerName
2. Dim_Date : All Possible Column like Date, Year, Month, Quarter etc..
3. Fact_Sales : CustID, InvoiceDate, SalesAmt

need soluation like :
when i select 3 months from slicer then i need to create column :  (Fact_Sales[SalesAmt]/(Number_of_Month Selected)) and create bucket like 0-100, 100-200, 200-500 etc. Group by with CustomerName/CustID and Customer count in bucket which we have created.

Need to show in Matrix
Row = State, City
Column = Bucket
Value = Distinct Count of CustID

Dyanamic Dimension

Please Find sample
Please Find Input output Detail of my Issue "Dyanamic Dimension from measure in Power BI "
https://www.dropbox.com/s/n8hrbv6sncgnquk/Copy%20of%20Issue%20Dynamic%20dimension.xls?dl=0
1 ACCEPTED SOLUTION

Accepted Solutions
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Moderator

Re: Dyanamic Dimension from measure in power bi

Hi @Vikram1,

You can create a new table like below:

Then create a measure below:

Measure = var t=SUMMARIZE('InPutData','InPutData'[State],InPutData[City],'InPutData'[CustID],"c1",DIVIDE(SUM('InPutData'[SalesQty]),DISTINCTCOUNT('InPutData'[InvoiceMonth])))
return
COUNTX(FILTER(t,[c1]>=MAX('Table1'[Start])&&[c1]<MAX('Table1'[End])),[CustID])

Best Regards,
Qiuyun Yu

Community Support Team _ Qiuyun Yu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
1 REPLY 1
Highlighted
Moderator

Re: Dyanamic Dimension from measure in power bi

Hi @Vikram1,

You can create a new table like below:

Then create a measure below:

Measure = var t=SUMMARIZE('InPutData','InPutData'[State],InPutData[City],'InPutData'[CustID],"c1",DIVIDE(SUM('InPutData'[SalesQty]),DISTINCTCOUNT('InPutData'[InvoiceMonth])))
return
COUNTX(FILTER(t,[c1]>=MAX('Table1'[Start])&&[c1]<MAX('Table1'[End])),[CustID])

Best Regards,
Qiuyun Yu

Community Support Team _ Qiuyun Yu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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