Division with Lookup

[learner4eva]

Hi,

I am trying to add a measure that computes this formula:

(Col3 when Col2=X )divided by (Col3 when Col2 = Y) for the each unique item in Col1.

Example: Col A has 3 uniques --> A, B, C

For Col1 = A, New Measure = 4/8 = 0.5

For Col1 = B, New Measure = 6/3 = 2

For Col1 = C, New Measure = 3/5 = 0.6

Thank you for your help

Col1	Col2	Col3
A	X	4
B	X	6
C	X	3
A	Y	8
B	Y	3
C	Y	5

[v-angzheng-msft · Accepted solution]

Hi, @learner4eva 

Try this:

Measure = 
var _a=CALCULATE(SUM('Table'[Col3]),FILTER(ALLEXCEPT('Table','Table'[Col1]),'Table'[Col2]="X"))
var _b=CALCULATE(SUM('Table'[Col3]),FILTER(ALLEXCEPT('Table','Table'[Col1]),'Table'[Col2]="Y"))
return DIVIDE(_a,_b)

result:

Please refer to the attachment below for details

Hope this helps.

Best Regards,
Community Support Team _ Zeon Zheng
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[Jihwan_Kim]

Result measure : =
VAR _x =
CALCULATE ( SUM ( Data[Col3] ), Col2[Col2] = "X" )
VAR _y =
CALCULATE ( SUM ( Data[Col3] ), Col2[Col2] = "Y" )
RETURN
IF ( HASONEVALUE ( Col1[Col1] ), DIVIDE ( _x, _y ) )

Link to the sample pbix file 

[ryan_mayu]

@learner4eva 

Pls try this

Measure = sumx(FILTER('Table','Table'[Col2]="X"),'Table'[Col3]/sumx(FILTER('Table','Table'[Col2]="Y"),'Table'[Col3]))

[amitchandak]

@learner4eva , Try a new measure like

divide(Sum(Table[Col3]), calculate(Sum(Table[Col3]), filter(allselected(Table), Table[Col1] = max(Table[Col1]) && Table[Col2] ="X")))