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ningty09
Helper I
Helper I

Divide elements of a column by the sum of another column while keeping filters on

Hi all,

 

I'm new to PoweBI and I'm looking for a way to divide the elements of a column by the total of another column while keeping filters on.

 

So for example:

A

B

date

12

87

9.16

16

32

9.16

56

35

9.17

 

What I want is the elements of A in date 9.16 divide by the sum of B in date 9.16, so:

A/B

date

12/(87+32)

9.16

16/(87+32)

9.16

 

I tried doing this in PowerBI

 

% AB= DIVIDE(SUM(table[A]),SUM(table[B]))

 

But it would give me

A/B

12/87

16/32

Which is not desired.

 

Futhermore I need to keep the date filter in, so I don't think ALL() would be approporiate.

 

Any kind of help would be highly appreciated!

1 ACCEPTED SOLUTION

Hi @ningty09 ,

 I created a measure to plement it with the function of ALLSELECTED.  The table still can be filtered by date.

Divide = DIVIDE(SUM('Table'[A]),CALCULATE(SUM('Table'[B]),FILTER(ALLSELECTED('Table'),'Table'[date] = MAX('Table'[date]))))

2.PNG3.PNG

Best Regards,

Xue Ding

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Best Regards,
Xue Ding
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
amitchandak
Super User
Super User

Hi, thanks for your reply.  However, I'm trying to use the measure in different visuals and there will be different filter based on each individual visual so I don't think this solution applies.

Hi @ningty09 ,

 I created a measure to plement it with the function of ALLSELECTED.  The table still can be filtered by date.

Divide = DIVIDE(SUM('Table'[A]),CALCULATE(SUM('Table'[B]),FILTER(ALLSELECTED('Table'),'Table'[date] = MAX('Table'[date]))))

2.PNG3.PNG

Best Regards,

Xue Ding

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Best Regards,
Xue Ding
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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