cancel
Showing results for
Did you mean:
ozlemv Frequent Visitor

## DistinctCount with filters

Hi everyone,

Hoping I could have help on the below issue.

I would like to calculate the distinct company ids whose actuals are higher than a fixed value (X)

Here's the formula I used:

ActivePartnerCount = IFERROR(CALCULATE( DISTINCTCOUNT(vTable1[CompanyID]),filter(vTable1,vTable1[Actuals]>X)),0)

If the fixed value(X) is 0, then the formulation is working, but not for other values.

1 ACCEPTED SOLUTION

Accepted Solutions v-huizhn-msft
Microsoft

## Re: DistinctCount with filters

Hi @ozlemv,

You use the IFERROR function in your formula, you create a calculated column based on my understanding.

IFERROR(A,B) := IF(ISERROR(A), B, A)

The following sub-formula in your formula is right. When the vTable1[Actuals]>X is ture, it will return a value, if the value of vTable1[Actuals] is 0, it will return 0, so the formula will return 0.

`CALCULATE( DISTINCTCOUNT(vTable1[CompanyID]),filter(vTable1,vTable1[Actuals]>X))`

As @Mi2n posted, you will get the expected result using the solution given.

If you have any other issue, please describe it clearly and sample data for further analysis.

Best Regards,
Angelia

5 REPLIES 5
MVP

## Re: DistinctCount with filters

Hi @ozlemv

How do you calculate your Fixed value 'X'?

Because it is fixed, you do not necessarily need filter function.

If X is fixed:

CALCULATE( DISTINCTCOUNT(vTable1[CompanyID]), vTable1[Actuals]>X) works and is exactly equivalent to

CALCULATE( DISTINCTCOUNT(vTable1[CompanyID]), Filter( All( vTable1[Actuals] , vTable1[Actuals]>X) )

Sean Super Contributor

## Re: DistinctCount with filters

Yes I don't see anything wrong with the Measure!

However I agree with @Datatouille we don't really know what X is - do you hardcode a number? If so it should work.

https://www.sqlbi.com/articles/filter-arguments-in-calculate/

Mi2n Member

## Re: DistinctCount with filters

My guess is, you have a calculated value for X instead of a fixed value. Is that right?

ozlemv Frequent Visitor

## Re: DistinctCount with filters

Hi all,

Actually X is a fixed number. Let's say it's 10000. The formulation is working when X equals to zero, but not with any other number. v-huizhn-msft
Microsoft

## Re: DistinctCount with filters

Hi @ozlemv,

You use the IFERROR function in your formula, you create a calculated column based on my understanding.

IFERROR(A,B) := IF(ISERROR(A), B, A)

The following sub-formula in your formula is right. When the vTable1[Actuals]>X is ture, it will return a value, if the value of vTable1[Actuals] is 0, it will return 0, so the formula will return 0.

`CALCULATE( DISTINCTCOUNT(vTable1[CompanyID]),filter(vTable1,vTable1[Actuals]>X))`

As @Mi2n posted, you will get the expected result using the solution given.

If you have any other issue, please describe it clearly and sample data for further analysis.

Best Regards,
Angelia

Announcements #### Meet the 2020 Season 1 Power BI Super Users!

It’s the start of a new Super User season! Learn all about the new Super Users and brand-new tiered recognition system. #### Super User Challenge: Can You Solve These?

We're celebrating the start of the New Super User season with our first ever Super User 'Can You Solve These?' challenge. #### Power BI Desktop Update - February 2020

We are super excited for our update this month, as we are releasing two of our top community requests! #### Power Platform Online Conference 