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Is it possible to get a distinct count of values in the ID column excluding any ID's that have a category value of 'D'
Using the below table as an example, the expected result would be '3': ID 1 + ID 3 + ID 4 = 3 unique ID's
ID 2 is excluded from the count as it has a category value of D.
ID | Category |
1 | A |
1 | B |
1 | C |
2 | A |
2 | B |
2 | C |
2 | D |
3 | A |
3 | B |
4 | A |
4 | B |
4 | C |
I've tried using DISTINCTCOUNT() with a filter like [Category] <> 'D' but this doesn't work as it will still include ID 2 in the count since ID 2 still pairs with category values other than D.
Thanks!
Solved! Go to Solution.
@lightw0rks , Try a measure like
countx(filter(summarize(Table, Table[ID],"_1", countx(filter(Table, Table[Category] ="D"),[Category])+0), [_1] =0),[ID])
@lightw0rks or you can use this measure:
Count =
VAR __tableWithD = CALCULATETABLE ( VALUES ( 'Test (2)'[ID] ), 'Test (2)'[Category] = "D" )
RETURN
COUNTROWS ( EXCEPT ( VALUES ( 'Test (2)'[ID] ), __tableWithD ) )
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@lightw0rks or you can use this measure:
Count =
VAR __tableWithD = CALCULATETABLE ( VALUES ( 'Test (2)'[ID] ), 'Test (2)'[Category] = "D" )
RETURN
COUNTROWS ( EXCEPT ( VALUES ( 'Test (2)'[ID] ), __tableWithD ) )
✨ Follow us on LinkedIn
Check my latest blog post The Power of Using Calculation Groups with Inactive Relationships (Part 1) (perytus.com) I would ❤ Kudos if my solution helped. 👉 If you can spend time posting the question, you can also make efforts to give Kudos to whoever helped to solve your problem. It is a token of appreciation!
⚡ Visit us at https://perytus.com, your one-stop-shop for Power BI-related projects/training/consultancy.⚡
Subscribe to the @PowerBIHowTo YT channel for an upcoming video on List and Record functions in Power Query!!
Learn Power BI and Fabric - subscribe to our YT channel - Click here: @PowerBIHowTo
If my solution proved useful, I'd be delighted to receive Kudos. When you put effort into asking a question, it's equally thoughtful to acknowledge and give Kudos to the individual who helped you solve the problem. It's a small gesture that shows appreciation and encouragement! ❤
Did I answer your question? Mark my post as a solution. Proud to be a Super User! Appreciate your Kudos 🙂
Feel free to email me with any of your BI needs.
@lightw0rks , Try a measure like
countx(filter(summarize(Table, Table[ID],"_1", countx(filter(Table, Table[Category] ="D"),[Category])+0), [_1] =0),[ID])
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