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Hicham Helper II
Helper II

Distinct count measure

Hi everyone,

I would like to do this measure : 

calculate the number of interventions using the distinctcount function for which there is neither the "A61" nor the "A62" intervention, but also does not take into account other interventions including the co-response codes A61 AND A62 Here is the table. Table name: Table.  So for this example, the result will be : 3

Another information: there are a lot of data like this. 

 

65+.PNG

Thank you, My best regards. 

1 ACCEPTED SOLUTION

Accepted Solutions
Super User I
Super User I

Re: Distinct count measure

Add a column that tracks if your Column1 has one A61/2 row
Has6162=
VAR thisOpCode=Table[Column1]
RETURN
IF(SUMX(FILTER(Table;Table[Column1]=thisOpCode);IF(Table[Column2] IN {"A61";"A62"};1;0))>=1;1;0)

 

this column will (should 🙂 ) contain 1 if that opcode has at least one A61, A62

 

Now your measure will count only the ones where that value is 0

Measure=DISTINCTCOUNT(FILTER(Table;Table[Has6162] =0);Table[Column1])


Check syntax and test, but should work





Did I answer your question? Mark my post as a solution!

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View solution in original post

1 REPLY 1
Super User I
Super User I

Re: Distinct count measure

Add a column that tracks if your Column1 has one A61/2 row
Has6162=
VAR thisOpCode=Table[Column1]
RETURN
IF(SUMX(FILTER(Table;Table[Column1]=thisOpCode);IF(Table[Column2] IN {"A61";"A62"};1;0))>=1;1;0)

 

this column will (should 🙂 ) contain 1 if that opcode has at least one A61, A62

 

Now your measure will count only the ones where that value is 0

Measure=DISTINCTCOUNT(FILTER(Table;Table[Has6162] =0);Table[Column1])


Check syntax and test, but should work





Did I answer your question? Mark my post as a solution!

PLEASE follow these instructions to ask your questions!


Proud to be a Super User!




View solution in original post

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