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Anonymous
Not applicable

Distinct Count based on two Columns - TRICKY

Hi Experts

 

How would you alter the formula as shown so 

 

OHA_OHP = CALCULATE(COUNTROWS(Data),FILTER(Data,Data[CaseType]="Face to Face Assessment"), CONTAINSROW({"IMA HML OHP OffSite","IMA HML OHP OnSite","IMA Network OHP","OHP Review 30 Minutes", "OHP Case Teleconference call (40 mins)"},Data[WorkType]))

 

So When CaseType Column is filter for Face to Face Assessment criteria and then we look at the work type column (here i need to count only distinct Values) as shown....

 

1 ACCEPTED SOLUTION
v-jiascu-msft
Employee
Employee

Hi @Anonymous,

 

Try this measure please.

OHA_OHP =
COUNTROWS (
    FILTER (
        ALL ( data[CaseType], data[WorkType] ),
        Data[CaseType] = "Face to Face Assessment"
            && data[WorkType]
            IN {
                "IMA HML OHP OffSite",
                "IMA HML OHP OnSite",
                "IMA Network OHP",
                "OHP Review 30 Minutes",
                "OHP Case Teleconference call (40 mins)" }
    )
)

Best Regards,

Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-jiascu-msft
Employee
Employee

Hi @Anonymous,

 

Try this measure please.

OHA_OHP =
COUNTROWS (
    FILTER (
        ALL ( data[CaseType], data[WorkType] ),
        Data[CaseType] = "Face to Face Assessment"
            && data[WorkType]
            IN {
                "IMA HML OHP OffSite",
                "IMA HML OHP OnSite",
                "IMA Network OHP",
                "OHP Review 30 Minutes",
                "OHP Case Teleconference call (40 mins)" }
    )
)

Best Regards,

Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

Hi Dale

 

Thank you!! Thank You....this was a pain to work out understand tour approah...

 

 

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