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mlavey24 Frequent Visitor
Frequent Visitor

Display MAX value of a Measure in a card visual based on the filtered Matrix

Hi,

 

I have a matrix visual that displays the 10 closest customers (measured in Kilometers) to another customer, based on an independent slicer selection.

 

Customer NameSales AmountDistance to Selected Customer
Cust1180.3
Cust2710.4
Cust31970.57
Cust4290.87
Cust5511.03
Cust651.03
Cust7921.3
Cust81541.56
Cust9101.62
Cust10132.41

 

The distance in Kilometers is calculated with the following DAX:

 

Distinace in Kilometers:=
VAR Lat1 =
    MIN ( 'Customer X'[Lat] )
VAR Lon1 =
    MIN ( 'Customer X'[Lon] )
VAR Lat2 =
    MIN ( 'Customer Y'[Lat] )
VAR Lon2 =
    MIN ( 'Customer Y'[Lon] )
VAR P =
    DIVIDE ( PI (), 180 )
VAR A =
    0.5
        - COS ( ( Lat2 - Lat1 ) * p ) / 2
        + COS ( Lat1 * p )
            * COS ( lat2 * P )
            * (
                1
                    - COS ( ( Lon2 - Lon1 ) * p )
            ) / 2
VAR Final =
    12742 * ASIN ( ( SQRT ( A ) ) )
RETURN
    Final

Ultimately, I want a dynamic measure that would display the maximum distance from CustX to CustY (in the above example, that would mean 2.41 Km) in a card visual and I am stumped.

1 ACCEPTED SOLUTION

Accepted Solutions
Community Support Team
Community Support Team

Re: Display MAX value of a Measure in a card visual based on the filtered Matrix

@mlavey24 

 

You may refer to the following post.

https://community.powerbi.com/t5/Desktop/DAX-formula-to-work-out-max-value-of-a-measure-HELP/td-p/44...

Community Support Team _ Sam Zha
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
Community Support Team
Community Support Team

Re: Display MAX value of a Measure in a card visual based on the filtered Matrix

@mlavey24 

 

You may refer to the following post.

https://community.powerbi.com/t5/Desktop/DAX-formula-to-work-out-max-value-of-a-measure-HELP/td-p/44...

Community Support Team _ Sam Zha
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

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