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QQQ
Advocate I
Advocate I

DAX to find percent of total based on filter (regardless of view)

How do I create DAX that finds the percent of incidents that are Status=Closed based on row view

 

Sample data from Power Pivot.

 

Total Incidents = Count of CREATED_DATE

 

I tried following Measure both gave error 

 

% Closed:=if(Table1[STATUS]="Closed",[Count of CREATED_DATE],0)/[Count of CREATED_DATE]

 

and

 

% Closed2:=DIVIDE(if(Table1[STATUS]="Closed",[Count of CREATED_DATE],0),[Count of CREATED_DATE],0)

 

sample_data.PNG

 

Here is my table

 

table.PNG

 

 

Here is what I wish to create. Please note, the % of Closed Incidents to Total should change based on how I filter the power-pivot, i.e. if I filter to include ONLY closed incidents, then naturally the % should be 100%

 

output.PNG

 

 

1 ACCEPTED SOLUTION
v-yuezhe-msft
Employee
Employee

@QQQ,

You can create the following measures in your table.

Total incidents = COUNT(Table[CREATE_DATE])
Count of closed = CALCULATE(COUNT(Table[CREATE_DATE]),FILTER(Table,Table[STATUS]="Closed"))
%closed = [Count of closed]/[Total incidents]
1.JPG2.JPG

If you have questions about the DAX, please share raw data of your table that can be copied and pasted, I will test it in my environment.

Regards,
Lydia

Community Support Team _ Lydia Zhang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
v-yuezhe-msft
Employee
Employee

@QQQ,

You can create the following measures in your table.

Total incidents = COUNT(Table[CREATE_DATE])
Count of closed = CALCULATE(COUNT(Table[CREATE_DATE]),FILTER(Table,Table[STATUS]="Closed"))
%closed = [Count of closed]/[Total incidents]
1.JPG2.JPG

If you have questions about the DAX, please share raw data of your table that can be copied and pasted, I will test it in my environment.

Regards,
Lydia

Community Support Team _ Lydia Zhang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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