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Regular Visitor

Cumulative total day of the month

I am trying to write a measure that calculates the cumulative total by day of month. Most of the measures I've written so far just give me a straight line across. The last one I wrote shows variation but it is not a running total. Any Ideas?

```BHC January 2018 Cumulative =
CALCULATE(
[BHC January 2018 Cohort],
FILTER(
ALL('Data Table'),
DAY('Data Table'[Date_Applied]) = MAX('Date Table'[DayOfMonth])
)
)```

1 ACCEPTED SOLUTION

Accepted Solutions
Super User

Re: Cumulative total day of the month

So, have to make a lot of assumptions to answer this. Have no idea what [BHC January 2018 Cohort] is. Assuming it is a measure that does some kind of SUM or something. Please see this post regarding How to Get Your Question Answered Quickly: https://community.powerbi.com/t5/Community-Blog/How-to-Get-Your-Question-Answered-Quickly/ba-p/38490

But, something like this should do it:

```BHC January 2018 Cumulative =
VAR currentday = MAX('Date Table'[DayOfMonth]

RETURN

CALCULATE(
[BHC January 2018 Cohort],
FILTER(
ALL('Data Table'),
DAY('Data Table'[Date_Applied]) <= currentday  )
)```

Did I answer your question? Mark my post as a solution!

Proud to be a Datanaut!

2 REPLIES 2
Super User

Re: Cumulative total day of the month

So, have to make a lot of assumptions to answer this. Have no idea what [BHC January 2018 Cohort] is. Assuming it is a measure that does some kind of SUM or something. Please see this post regarding How to Get Your Question Answered Quickly: https://community.powerbi.com/t5/Community-Blog/How-to-Get-Your-Question-Answered-Quickly/ba-p/38490

But, something like this should do it:

```BHC January 2018 Cumulative =
VAR currentday = MAX('Date Table'[DayOfMonth]

RETURN

CALCULATE(
[BHC January 2018 Cohort],
FILTER(
ALL('Data Table'),
DAY('Data Table'[Date_Applied]) <= currentday  )
)```

Did I answer your question? Mark my post as a solution!

Proud to be a Datanaut!

Regular Visitor

Re: Cumulative total day of the month

That did it! Thanks so much for the help.