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Helper I
Helper I

Count of Sales needed

HI all,

 

I am looking to do 2 different measures which gives me the following: - 

 

 - for each date, I want to see the last 7 days of sales 

 - for each date, I want to see the last 30 days of sales

 

Example: - Today, I want to see that yesterdays date contains the count of sales for (22nd, 21st, 20th, 19th, 18th, 17th & 16th) which would then mean that 21st date would contact count of sales from 21st - 15th) - Of course the other measure should be doable by amending this one.

 

In my table, 

 

Hope that makes sense.

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Hi @TheLegendTamer 

 

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Community Support Team _ Dina Ye
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View solution in original post

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Community Champion

@TheLegendTamer 

Can you share some sample data and the expected result to have a clear understanding of your question?
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Thanks for your reply.

 

The below is what I am hoping for - dont have any sample data yet im afraid.

 

3 measures in total - yesterday which is fine. Then last 7 days and last 30 days. So looking at yesterdays date on the 'x' axis it gives sum of sales from yesterday, last 7 days from yesterday and last 30 days from yesterday.

 

TheLegendTamer_0-1600857159862.png

 

you can use something like 

 

Rolling 7 Day Amount = CALCULATE(SUM(table[Value]),DATESINPERIOD(DimDate[Date],MAX(DimDate[Date]),-7,DAY))
 
Rolling 30 Day Amount = CALCULATE(SUM(table[Value]),DATESINPERIOD(DimDate[Date],MAX(DimDate[Date]),-30,DAY))
Did I answer your question? Mark my post as a solution! Appreciate your Kudos!!

Diamond! Thank you muchly

Hi @TheLegendTamer 

 

If the above posts help, please kindly mark it as a answer to help others find it more quickly. thanks!

If not, please kindly elaborate more.

 

Community Support Team _ Dina Ye
If this post helps, then please consider Accept it as the solution to help the other members find it more
quickly.

I have marked it as a thumbs up, doesnt this mean its the answer?

Hi @TheLegendTamer 

 

You can mark it as answer by clicking below option:

009.PNG

Community Support Team _ Dina Ye
If this post helps, then please consider Accept it as the solution to help the other members find it more
quickly.

View solution in original post

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