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joyo Frequent Visitor
Frequent Visitor

Converting Decimal number into Binary

My apologies I don't understand this.

https://community.powerbi.com/t5/Desktop/Number-to-Binary/m-p/235261#M104739

 

Here is my Data 

binary.PNG    

 

I have a column name Config which contains decimal number 1 to 14. I want to create a new column config2 and convert config column into binary (base2).

eg. config2 =(config binary (base2))

*Config |Config2*

          1 |0001

          2 |0010

          3 |0011

1 ACCEPTED SOLUTION

Accepted Solutions
Microsoft v-jiascu-msft
Microsoft

Re: Converting Decimal number into Binary

Hi @joyo,

 

To be honest, I don't understand it for now. But I can make it work.

1. Change a little to make it work as a function. (The code is quoted from this post: Number-to-Binary)

let
    fnNBC = (input as anynonnull, base as number, optional outputlength as number) as any =>
    let
        //    input = 10,
        //    base = 2,
        //    outputlength = null,
        Base16 = "0123456789ABCDEF",
        Base32 = "ABCDEFGHIJKLMNOPQRSTUVWXYZ234567",
        Base64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/",
        Lookups = List.Zip({{16,32,64},{Base16,Base32,Base64}}),
        Lookup = Text.ToList(List.Last(List.Select(Lookups,each _{0} <= List.Max({16, base}))){1}),
        InputToList = Text.ToList(input),

        // This part will be executed if input is text:
            Reversed = List.Reverse(InputToList),
            BaseValues = List.Transform(Reversed, each List.PositionOf(Lookup,_)),
            Indexed = List.Zip({BaseValues, {0..Text.Length(input)-1}}),
            Powered = List.Transform(Indexed, each _{0}*Number.Power(base,_{1})),
            Decimal = List.Sum(Powered),
        // So far this part

        // This part will be executed if input is not text:
            Elements = 1+Number.RoundDown(Number.Log(input,base),0),
            Powers = List.Transform(List.Reverse({0..Elements - 1}), each Number.Power(base,_)),
            ResultString = List.Accumulate(Powers,
                                          [Remainder = input,String = ""], 
                                          (c,p) => [Remainder = c[Remainder] - p * Number.RoundDown(c[Remainder] / p,0),
                                                    String = c[String] & Lookup{Number.RoundDown(c[Remainder]/p,0)}])[String],    
            PaddedResultString = if outputlength = null then ResultString else Text.PadStart(ResultString,outputlength,Lookup{0}),
        // So far this part

        Result = if input is text then Decimal else PaddedResultString
    in
        Result
    in
fnNBC

2. Create a blank query, paste the code above. And change its name to "ToBinary".Converting Decimal number into Binary.jpg

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

3. Add a custom column.

=Text.PadStart(ToBinary([Column1], 2), 4, "0")

Converting Decimal number into Binary1.jpg

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

4. Done.

 

NOTE: The code above is quoted from https://community.powerbi.com/t5/Desktop/Number-to-Binary/m-p/235261#M104739

 

Best Regards!

Dale

 

 

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
Microsoft v-jiascu-msft
Microsoft

Re: Converting Decimal number into Binary

Hi @joyo,

 

To be honest, I don't understand it for now. But I can make it work.

1. Change a little to make it work as a function. (The code is quoted from this post: Number-to-Binary)

let
    fnNBC = (input as anynonnull, base as number, optional outputlength as number) as any =>
    let
        //    input = 10,
        //    base = 2,
        //    outputlength = null,
        Base16 = "0123456789ABCDEF",
        Base32 = "ABCDEFGHIJKLMNOPQRSTUVWXYZ234567",
        Base64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/",
        Lookups = List.Zip({{16,32,64},{Base16,Base32,Base64}}),
        Lookup = Text.ToList(List.Last(List.Select(Lookups,each _{0} <= List.Max({16, base}))){1}),
        InputToList = Text.ToList(input),

        // This part will be executed if input is text:
            Reversed = List.Reverse(InputToList),
            BaseValues = List.Transform(Reversed, each List.PositionOf(Lookup,_)),
            Indexed = List.Zip({BaseValues, {0..Text.Length(input)-1}}),
            Powered = List.Transform(Indexed, each _{0}*Number.Power(base,_{1})),
            Decimal = List.Sum(Powered),
        // So far this part

        // This part will be executed if input is not text:
            Elements = 1+Number.RoundDown(Number.Log(input,base),0),
            Powers = List.Transform(List.Reverse({0..Elements - 1}), each Number.Power(base,_)),
            ResultString = List.Accumulate(Powers,
                                          [Remainder = input,String = ""], 
                                          (c,p) => [Remainder = c[Remainder] - p * Number.RoundDown(c[Remainder] / p,0),
                                                    String = c[String] & Lookup{Number.RoundDown(c[Remainder]/p,0)}])[String],    
            PaddedResultString = if outputlength = null then ResultString else Text.PadStart(ResultString,outputlength,Lookup{0}),
        // So far this part

        Result = if input is text then Decimal else PaddedResultString
    in
        Result
    in
fnNBC

2. Create a blank query, paste the code above. And change its name to "ToBinary".Converting Decimal number into Binary.jpg

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

3. Add a custom column.

=Text.PadStart(ToBinary([Column1], 2), 4, "0")

Converting Decimal number into Binary1.jpg

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

4. Done.

 

NOTE: The code above is quoted from https://community.powerbi.com/t5/Desktop/Number-to-Binary/m-p/235261#M104739

 

Best Regards!

Dale

 

 

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

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