Column with text and numbers

[Anonymous]

I have a column formated as text with 2 types of data. 1) 12345 and 2) AB123. Now I am looking for a way to have in another column the Values of 1 as values and the first 2 letters of 2 as text. It is needed to make a connection to another table in which the values and the letters are connected to cities.

An idea is welcome.

[v-juanli-msft]

Hi @Anonymous 

If i understand you correct, you want

column         ->   column1   column2

12345                  12345        AB

AB123

If so, in Edit queries,

1. add two column

2.Replace errors with null

3.add conditional column

4.Fill down for "Custom" column

5.Filter Rows which is null for 'Custom.1"

6. remove columns

Then Whole code in Advanced editor

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjQyNjFVitWJVnJ0ArLBLEMjE1MzMMvZBchWio0FAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type text) meta [Serialized.Text = true]) in type table [column = _t]),
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"column", type text}}),
    #"Added Custom" = Table.AddColumn(#"Changed Type", "Custom", each Number.FromText([column])),
    #"Inserted First Characters" = Table.AddColumn(#"Added Custom", "First Characters", each Text.Start([column], 2), type text),
    #"Replaced Errors" = Table.ReplaceErrorValues(#"Inserted First Characters", {{"Custom", null}}),
    #"Added Conditional Column" = Table.AddColumn(#"Replaced Errors", "Custom.1", each if [Custom] = null then 1 else null),
    #"Filled Down" = Table.FillDown(#"Added Conditional Column",{"Custom"}),
    #"Filtered Rows" = Table.SelectRows(#"Filled Down", each [Custom.1] <> null and [Custom.1] <> ""),
    #"Removed Columns" = Table.RemoveColumns(#"Filtered Rows",{"column", "Custom.1"})
in
    #"Removed Columns"

Best Regards
Maggie

Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[Anonymous · Accepted solution]

My solution was:  

to get the value in a new Column:

ProductValue = VALUE(database[column])

and for the first 2 letters

ProductID = LEFT(database[column];2)

Very simple but it it does what is needed.