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Murali777
Helper III
Helper III

Calculated Table for distinct Email Id as Key and most recent value of Name

I need derived table for distinct email id with the latest first name and last name based on latest registration date time colum (DateTime column). Please find the below example for your reference.

 

Murali777_0-1655989129714.png

 

Kindly anyone pls help me.

 

@amitchandak @Icey @Jihwan_Kim 

 

1 ACCEPTED SOLUTION

@Murali777 , DAX code

filter(addcolumns(Table, "_Max", maxx(filter(Table, Table[Email] = earlier([Email])), [registration Date])), [_Max] = [registration Date])

 

or

new Table  =

Var _1 = addcolumns(Table, "_Max", maxx(filter(Table, Table[Email] = earlier([Email])), [registration Date]))

return

calculatetable(_1, filter(_1, [_Max] = [registration Date]) )

 

View solution in original post

5 REPLIES 5
amitchandak
Super User
Super User

Hi Amit,

 

I need code for calculated table not in the query editor. Kindly help me for DAX code for calculated Table.

@Murali777 , DAX code

filter(addcolumns(Table, "_Max", maxx(filter(Table, Table[Email] = earlier([Email])), [registration Date])), [_Max] = [registration Date])

 

or

new Table  =

Var _1 = addcolumns(Table, "_Max", maxx(filter(Table, Table[Email] = earlier([Email])), [registration Date]))

return

calculatetable(_1, filter(_1, [_Max] = [registration Date]) )

 

Hi Amit,

 

Thanks for your code and your code is almost working. but my challenge is, i'm having bunch of columns and it returns all the column. 

 

I want only the 3 columns (Email, First Name, Last Name) in the calculated table.

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