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Helper II

## Calculate total and ratio

I Want to learn how to write dax code in two ways ( Calculated Column and Measure)

to formulate total by "PriodID" and "Ratio"

1 ACCEPTED SOLUTION

Accepted Solutions
Community Support

Hi @MrDarian ,

Check

``````Measure 1 = CALCULATE(SUM('Table'[Indicator]),ALLEXCEPT('Table','Table'[PeriodID]))

Measure 2 = SELECTEDVALUE('Table'[Indicator])/[Measure 1]

Column 1 = CALCULATE(SUM('Table'[Indicator]),ALLEXCEPT('Table','Table'[PeriodID]))

Column 2 = 'Table'[Indicator]/'Table'[Column 1]``````

Best Regards,

Jay

Community Support Team _ Jay
If this post helps, then please consider Accept it as the solution to help the other members find it.
4 REPLIES 4
Resolver III

Hi @MrDarian ,

Please share an example of what calculations you want to perform.

Thank you

Super User IV

Try

New column = divide([indicator], sumx(filter(table,[PriodID] = earlier([PriodID])),[indicator]))

New measure = divide(sum([indicator]), sumx(filter(allselected(table),[PriodID] = Max([PriodID])),[indicator]))
New measure = divide(sum([indicator]), sumx(filter((table),[PriodID] = Max([PriodID])),[indicator]))

Proud to be a Super User!

Resolver I

Hi @MrDarian :

PFB Calculated column and measure :

``CalculatedColumnSum = CALCULATE(SUM('Table'[Indicator]),ALLEXCEPT('Table','Table'[PeriodID]))``

``````CalculatedColumRatio =
Var _IndicatorByPeriod= CALCULATE(SUM('Table'[Indicator]),ALLEXCEPT('Table','Table'[PeriodID]))
Var _Result= DIVIDE('Table'[Indicator],_IndicatorByPeriod,0)
Return
_Result``````

``MeasureSum = CALCULATE(SUM('Table'[Indicator]),ALLEXCEPT('Table','Table'[PeriodID]))``

``MeasureRatio = DIVIDE(SUMX(FILTER('Table','Table'[PeriodID]=MAX('Table'[PeriodID])),'Table'[Indicator]),[MeasureSum],0)``

Thanks!

Community Support

Hi @MrDarian ,

Check

``````Measure 1 = CALCULATE(SUM('Table'[Indicator]),ALLEXCEPT('Table','Table'[PeriodID]))

Measure 2 = SELECTEDVALUE('Table'[Indicator])/[Measure 1]

Column 1 = CALCULATE(SUM('Table'[Indicator]),ALLEXCEPT('Table','Table'[PeriodID]))

Column 2 = 'Table'[Indicator]/'Table'[Column 1]``````

Best Regards,

Jay

Community Support Team _ Jay
If this post helps, then please consider Accept it as the solution to help the other members find it.

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