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Anonymous
Not applicable

Calculate percentage from same column

Hello,

 

I was wondering if there is a way to calculate the percentage of a value in a column based on a different value in the same column. To do this I'd like to use a different column as an index.

For instance, on the attached picture, I would like to calculate the percentage of Total Labor on Total Cost.

 

Thanks for your time.

Capture8321412.JPG

1 ACCEPTED SOLUTION

Accepted Solutions
HarrisonCbe Member
Member

Re: Calculate percentage from same column

Hello @Anonymous

 

Try this please:

 

Percentage= DIVIDE(CALCULATE(SUM(Table[Month Budget]);FILTER(Table;Table[Category]="Total Labor"));CALCULATE(SUM(Table[Month Budget]);FILTER(Table;Table[Category]="Total Cost")))

 

I hope this works.

 

PS, in "Table", you've to put the name of the table.

3 REPLIES 3
HarrisonCbe Member
Member

Re: Calculate percentage from same column

Hello @Anonymous

 

Try this please:

 

Percentage= DIVIDE(CALCULATE(SUM(Table[Month Budget]);FILTER(Table;Table[Category]="Total Labor"));CALCULATE(SUM(Table[Month Budget]);FILTER(Table;Table[Category]="Total Cost")))

 

I hope this works.

 

PS, in "Table", you've to put the name of the table.

Anonymous
Not applicable

Re: Calculate percentage from same column

Sorry, I didn't fully explain my situation. I have dozens of clients and every client has those 5 rows with a client ID. Your solution, while elegant, it will only work if there was only one set if clients.

 

I ended up splitting the table into 5 smaller tables each containing one category and then doing calculations that way. I know it's not clean.

Community Support Team
Community Support Team

Re: Calculate percentage from same column

Hi @Anonymous

 

It seems you may use "Append Queries" in query editor to combine the tables. Then you may use the measure as HarrisonCbe mentioned. If it is not your case, please share sample data for your scenario so that we could help further on it.

 

Regards,

Cherie

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.