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Frequent Visitor

## Calculate difference in times excluding times between a range

Hi All,

I'm trying to calculate the difference in times from datetimestamp columns (Start & End) but need to exclude times between 2 times and the result is in hours and minutes.

In the example below, the period to exclude is between 10PM to 4AM and is based on Start and End slicers i.e. only calculate the times from 4AM to 10PM.

 Scenario Start End End - Start Correct Time Fault 1 - Start >= 4AM & End < 10PM 10/03/2022 06:25 10/03/2022 09:15 02:50 02:50 Fault 2 - Start < 4AM & End < 10PM 11/03/2022 03:00 11/03/2022 10:30 07:30 06:30 Fault 3 - Start >= 4AM & End >= 10PM 12/03/2022 21:10 12/03/2022 23:30 02:20 00:50 Fault 4 - Start >= 10PM & End < 4AM (before midnight) 13/03/2022 23:00 13/03/2022 23:30 00:30 00:00 Fault 5 - Start >= 10PM & End < 4AM (end +1 day) 14/03/2022 22:30 15/03/2022 02:30 04:00 00:00 Fault 6 - Start >=10PM & End >= 4AM 15/03/2022 22:30 16/03/2022 04:30 06:00 00:30 Fault 7 - Start < 10PM & End >= 4AM (end +2 days) 16/03/2022 19:00 18/03/2022 05:00 10:00 22:00

I've tried creating calculated columns to adjust the Start and End times which kind of works but not if the End is more than 1 day.

I have this Excel formula which kind of works;

=IF(End<Start,"Check Value", MAX(0,TIME(22,0,0)-MAX(MOD(Start,1),TIME(4,0,0)))+MAX(0,MIN(MOD(End,1),TIME(22,0,0))-TIME(4,0,0))+(INT(End)-INT(Start)-1)*TIME(18,0,0))

Many thanks.

1 ACCEPTED SOLUTION
Community Support

Hi @M0n5ta09 ,

Yes, it is easier to work in minutes.

When I converted minutes to time, I made some mistakes. Please try this code.

``````Column =
VAR _a =
GENERATESERIES ( [Start], [End], TIME ( 0, 1, 0 ) )
VAR _filter =
FILTER (
_a,
TIMEVALUE ( [Value] ) > TIME ( 3, 59, 59 )
&& TIMEVALUE ( [Value] ) <= TIME ( 21, 59, 59 )
)
VAR _m =
COUNTROWS ( _filter )
RETURN
ROUNDDOWN ( _m / 60, 0 ) & ":"
& MOD ( _m, 60 )
``````

Best Regards

Community Support Team _ chenwu zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

4 REPLIES 4
Community Support

Hi @M0n5ta09 ,

Please try this expression to do it:

``````Column =
VAR _a =
GENERATESERIES ( [Start], [End], TIME ( 0, 1, 0 ) )
VAR _filter =
FILTER (
_a,
TIMEVALUE ( [Value] ) > TIME ( 3, 59, 59 )
&& TIMEVALUE ( [Value] ) <= TIME ( 21, 59, 59 )
)
RETURN
TIME ( 0, COUNTROWS ( _filter ), 0 )
``````

Result:

Pbix in the end you can refer.

Best Regards

Community Support Team _ chenwu zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Frequent Visitor

Thank you. Apologies for the delay reply.

This works for a majority but not with these Start and End. I'm guessing because the hours are over 24;

 Fault Start End Column 1 30/04/2022 10:58:04 01/05/2022 21:20:00 4:22:00 2 01/05/2022 13:00:00 03/05/2022 19:30:00 18:30:00

Fault 1:

10:58 to 22:00 = 11:02 or 662 minutes

04:00 to 21:20 = 17:20 or 1040 minutes

Result should be 11:02 + 17:20 = 18:22 or 1102 minutes

Fault 2:

01/05/2022 13:00 to 22:00 = 9:00 or 540 minutes

02/05/2022 04:00 to 22:00 = 18:00 or 1080 minutes

03/05/2022 04:00 to 19:30  = 15:30 or 930 minutes

Result should be 9:00 + 18:00 + 15:30 = 42:30:00 or 2550 minutes

Is it easier to work in minutes and convert to time afterwards?

Community Support

Hi @M0n5ta09 ,

Yes, it is easier to work in minutes.

When I converted minutes to time, I made some mistakes. Please try this code.

``````Column =
VAR _a =
GENERATESERIES ( [Start], [End], TIME ( 0, 1, 0 ) )
VAR _filter =
FILTER (
_a,
TIMEVALUE ( [Value] ) > TIME ( 3, 59, 59 )
&& TIMEVALUE ( [Value] ) <= TIME ( 21, 59, 59 )
)
VAR _m =
COUNTROWS ( _filter )
RETURN
ROUNDDOWN ( _m / 60, 0 ) & ":"
& MOD ( _m, 60 )
``````

Best Regards

Community Support Team _ chenwu zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Frequent Visitor

Thank so much @v-chenwuz-msft

Works perfectly 👍

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