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Hello community,
here I am with my next issue. I have following problem which i started with an extra column and a formula unfortunately it brings me no further..
=search("183";lagerbew[LS_Nr.2];1;0)
So i have one column with many different No. of Deliverynotes and Purchasenotes. Now I want to count the different Delieverynumbers in this column. But not dubble ones...
The DN numbers start with 183... and are 7 digits long.
I tried to work it out with an extra column but actually it makes no sence..
Can anyone help me? Sorry i am still this bloody beginner ...
thanks in advance already..
bumble_bee
Solved! Go to Solution.
Hi,
This may not be the cleanest solution, but you could try:
Measure = COUNTROWS(DISTINCT(FILTER('Sheet1',Sheet1[lfdnr_ls]>999999)))
Hi,
This may not be the cleanest solution, but you could try:
Measure = COUNTROWS(DISTINCT(FILTER('Sheet1',Sheet1[lfdnr_ls]>999999)))
hey sduffy,
nice and simple smart approach, and yes it works.. I found then also a solution by myself through your idea with >999999:
countax(filter(lagerbew;lagerbew[lfdnr_ls]>999999);["measure"countrows])
However you brought me the solution. thank you very much.. and have a good day
cheers bb
to all who might look for the same issue,
i have to correct myself... best solution should be:
=CALCULATE(DISTINCTCOUNT(lagerbew[lfdnr_ls]);filter(lagerbew;lagerbew[lfdnr_ls]>999999);lagerbew[lfdnr_ls])
sorry i was too fast before.. with this solution i do count only all unicque values i want..
thx
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