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Hi,
I need to use LEFT() function for each row in table so as a measure in 'row context'. Because my report is based on powerBI dataset, I am unable to use LEFT() as a new column (this operation is unavailable)
Any idea how to do it?
thx a lot !
Solved! Go to Solution.
Hi @Mariusz
I would like get something like this
Batch No. | LEFT(Batch No.;3) |
123123 | 123 |
123456 | 123 |
123789 | 123 |
987987 | 987 |
987654 | 987 |
987321 | 987 |
But I cannot solve it as 'new column', where it is easy to set up
Hi @ph
Please see the below
Measure = LEFT( MAX( 'Table'[Batch No.] ), 3 )
[First 3 Chars for Batch No.] = -- measure var __oneBatchVisible = HASONEFILTER( T[Batch No.] ) var __chars = if ( __oneBatchVisible, var __currentBatch = VALUES( T[Batch No.] ) var __first3Chars = left( __currentBatch, 3 ) return __first3Chars ) RETURN __chars
Best
D.
Hi @Mariusz
I would like get something like this
Batch No. | LEFT(Batch No.;3) |
123123 | 123 |
123456 | 123 |
123789 | 123 |
987987 | 987 |
987654 | 987 |
987321 | 987 |
But I cannot solve it as 'new column', where it is easy to set up
[First 3 Chars for Batch No.] = -- measure var __oneBatchVisible = HASONEFILTER( T[Batch No.] ) var __chars = if ( __oneBatchVisible, var __currentBatch = VALUES( T[Batch No.] ) var __first3Chars = left( __currentBatch, 3 ) return __first3Chars ) RETURN __chars
Best
D.
Hi both
thank you for your help 🙂
I accept as solution the first one, because it is easier to understand it, second one is more complicated ..but works fine !!
Hi @ph
Please see the below
Measure = LEFT( MAX( 'Table'[Batch No.] ), 3 )
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