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Hi Guys,
I thought I knew how to handle Dax, but now I am starting to get frustrated about solving the following Problem:
I want a Running Count for the concecutive Year/Quarter/Month/Day a Company generated Revenue. I already managed to Flag the result thourgh the Hierarchy with the Value 1 if its true and 0 if Not.
But the real challenge, where I'm struggeling right now, is to do a running Count on Consecutive Days/Month/Quarter/Years.
So far I haven't found a Way to achieve this. The red numbers would be the desired result.
And here of course the Code for the simple_flag Measure:
Please let me know if you need more Information about my Problem.
I Thank you all in advanced for at leas giving me a hint how to do it, because so far I truly see no Chance of solving that.
Markus
Hi @Anonymous
Please refer to the below, it's not a full solution but it should give you an idea.
Measure 15 =
VAR __countDays = COUNTROWS( 'Calendar' )
VAR __countAllDaysInYear = COUNTROWS( CALCULATETABLE( 'Calendar', ALL( 'Calendar' ), VALUES( 'Calendar'[Year] ) ) )
VAR __countAllDaysInMonth = COUNTROWS( CALCULATETABLE( 'Calendar', ALL( 'Calendar' ), VALUES( 'Calendar'[Year Month] ) ) )
VAR __rankYear = RANKX( ALLSELECTED( 'Calendar'[Year] ), [Sales] )
VAR __rankMonth = RANKX( ALLSELECTED( 'Calendar'[Year Month], 'Calendar'[yearMonthNo] ), [Sales] )
RETURN
SWITCH(
TRUE(),
__countDays = __countAllDaysInYear, __rankYear,
__countDays = __countAllDaysInMonth, __rankMonth
)
This is the result
Hi Mariusz,
thanks for looking into this.
I really like the Idea of combining COUNTROWS with RANKX-Function.
I'm pretty sure that's the approach how to solve that problem.
I tried something similar, but do you see a way, to start the Rank again in
Case there was no sale on the hierarchy level?
Lets assume there was no Sale at a certain day, so the flag would be 0 for that day.
If there was a sale the next day, the Flag should start with 1 again, and add up as long as
the series continues until it finally gets to a day without Sale and 0 again.
Again thank you so much for talking the time.
Of course if I'll find the final Solution I'll let you know
Markus
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