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giordafrancis
Frequent Visitor

Counting duplicate entries and displaying it on table

Consider the table below;


I'm looking to create a measure that shows  the duplicate count on count name Id pairs without having to create the intermediate calculated column name Id pairs. 
Thank you in advance for your time and assistance.

names                                 
ID                                
 name - ID Pairs                    
count name - ID pairs
smith1100smith 11002
borke0012borke 00121
smith1100smith 11002
travis1234travis 12341
amadeus0987amadeus 09871
1 ACCEPTED SOLUTION
harshnathani
Community Champion
Community Champion

Hi @giordafrancis ,

 

Create a measure

 

Duplicates =

var _a = CONCATENATE(MAX('Table'[Name]),MAX('Table'[ID]))

RETURN
COUNTX('Table',_a)
 
1.jpg
 

Regards,
Harsh Nathani

Did I answer your question? Mark my post as a solution! Appreciate with a Kudos!! (Click the Thumbs Up Button)

View solution in original post

2 REPLIES 2
harshnathani
Community Champion
Community Champion

Hi @giordafrancis ,

 

Create a measure

 

Duplicates =

var _a = CONCATENATE(MAX('Table'[Name]),MAX('Table'[ID]))

RETURN
COUNTX('Table',_a)
 
1.jpg
 

Regards,
Harsh Nathani

Did I answer your question? Mark my post as a solution! Appreciate with a Kudos!! (Click the Thumbs Up Button)

stevedep
Memorable Member
Memorable Member

Here you go:

CountPairs = 
var __tbl = SUMMARIZE('Table';'Table'[ID];'Table'[names];"c";COUNTROWS('Table'))
return
MINX(__tbl; [c])

As seen here:

paris.gif

 

File is here.

 

Please mark as solution if this is what you are looking for. Thumbs up for the effort is appreciated.

 

Kind regards, Steve. 

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