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Helper I
Helper I

Average of Averages

Hi everyone,

 

I'm struggling to handle an easy formula which is a nested average computed along a table with 2 dimension (AUTORE,LINK).

Basically I need to compute first of all an average for each author (AUTORE), and then use those aggregated values to create a second level average.

 

AUTORE LINK VALORE
autore_1 url_A 20
autore_1 url_B 20
autore_1 url_C 20
autore_1 url_D 20
autore_1 url_E 10
autore_1 url_F 10
autore_2 url_G 20
autore_3 url_H 5

 

For those familiar with Tableau, you could get the correct result with a nested Level of Deatil2020-04-29 19_27_19-Window.png

 

I've already checked a similar post (https://community.powerbi.com/t5/Desktop/Average-of-average/m-p/1017894#M481085) but I'm not sure I'm understanding 100%, especially in my case where I have 2 dimension columns and one of them (LINK) is not involved in that caluclus.

 

Can anyone help?

 

Thanks in advance.

 

 

Fabio

Follow me on Twitter:@PantoMvp
Get in contact on Linkedin: Fabio Fantoni
1 ACCEPTED SOLUTION

Accepted Solutions
Highlighted
Super User IX
Super User IX

Re: Average of Averages

The general pattern is:

 

Measure = 

  AVERAGEX(

    SUMMARIZE(

      'Table',

      [Group],

      "__Average",AVERAGE('Table'[Column])

    ),

    [__Average]

  )


---------------------------------------

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View solution in original post

2 REPLIES 2
Highlighted
Super User IX
Super User IX

Re: Average of Averages

The general pattern is:

 

Measure = 

  AVERAGEX(

    SUMMARIZE(

      'Table',

      [Group],

      "__Average",AVERAGE('Table'[Column])

    ),

    [__Average]

  )


---------------------------------------

Not link spamming! If I posted a link in reply it is because I did assume you know how to search the web but thought it was the fastest way to fix your issue.

I have a NEW book! 
DAX Cookbook from Packt
Over 120 DAX Recipes!




Did I answer your question? Mark my post as a solution!

Proud to be a Super User!




View solution in original post

Highlighted
Helper I
Helper I

Re: Average of Averages

 Hi @Greg_Deckler 

 

thanks for your feedback.

 

It's exactly what I was looking for.

 

 

Regards

Follow me on Twitter:@PantoMvp
Get in contact on Linkedin: Fabio Fantoni

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